Two resistors, one with a resistance of 3.0 Ω and another with a resistance of 6.0 Ω, are connected in parallel across a 12 V battery. What is the total current drawn from the battery by this parallel combination?

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• A 1.3 A
• B 4.0 A
• C 6.0 A
• D 9.0 A

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Answer: C. 6.0 A

For resistors in parallel: 1/Rp = 1/3.0 + 1/6.0 = 3/6.0, so Rp = 2.0 Ω. By Ohm's law, I = V/R = 12 V ÷ 2.0 Ω = 6.0 A.

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