In the following sequence how many times 7 is succeeded by even number and preceded by 5.

23456718957033456572338907523189574389216.

Answer: C. 3

The answer is C. 3.
To find the answer, we look for the pattern 5-7-[Even Number] (where an even number is 0, 2, 4, 6, or 8):
...9 5 7 0 3... (7 is preceded by 5 and followed by 0, which is even)
...5 5 7 2 3... (7 is preceded by 5 and followed by 2, which is even)
...9 5 7 4 3... (7 is preceded by 5 and followed by 4, which is even)
There are 3 times this happens in the sequence.

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