If x^3=1728 find the value of x.

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A 12
B 22
C 14
D 32

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Answer: A. 12

We need a number whose cube is 1728. 12 x 12 = 144 and 144 x 12 = 1728, so x = 12. 1728 ends in 8, which also points to a root ending in 2.

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If x^3=1728 find the value of x.

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