How much money would Joanne save if she bought two bowls and two plates instead?
Given:
She paid a total of $ 52 for 2 similar bowls and 4 similar plates.
5 bowls cost as much as 3 plates.

Answer: C. $ 20

Let B be bowl and P be plate. 2B + 4P = 52 and 5B = 3P.
Substituting B gives: 2(3/5P) + 4P = 52.
Solving for P: (26/5)P = 52, so P = 10 and B = 6.
New cost for 2B + 2P = 12 + 20 = 32.
Savings = 52 - 32 = $ 20

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