For what exact value of the constant k will the pair of linear equations kx + 3y = k - 3 and 12x + ky = k have infinitely many solutions?

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A k = 3
B k = -6
C k = 6
D k = 0

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Answer: C. k = 6

Answer: C) k = 6
Explanation: For infinitely many solutions, a1/a2 = b1/b2 = c1/c2.
k/12 = 3/k gives k² = 36, so k = ±6.
Checking the constants: 3/k = (k - 3)/k holds only for k = 6 (3/6 = 3/6).

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For what exact value of the constant k will the pair of linear equations kx + 3y = k - 3 and 12x + ky = k have infinitely many solutions?

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