Mental Maths Class 5 Integers

Asked by AKSHAY GURU VARADHARAJAN · SRI CHAITANYA TECHNO SCHOOL, JAYANTI NAGAR.

Find the smallest number which leaves a remainder of 1 when divided by 2, 3, 4 and 5.

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Answer: C. 61

A number leaving remainder 1 on division by 2, 3, 4 and 5 is 1 more than a common multiple of them. LCM(2, 3, 4, 5) = 60, so the smallest such number is 60 + 1 = 61.

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