Binod prepared 150 meatballs for 36 pupils.
1/2 of the pupils took 5 meatballs each and 1/6 of them took 2 meatballs each.
The rest of the meatballs were then distributed equally among the remaining pupils.
a) How many meatballs were distributed to the remaining pupils altogether?
b) How many meatballs did each of the remaining pupils take?

Answer: C. 48,4

Group 1: 1/2 of 36 pupils = 18 pupils. They took 18 * 5 = 90 meatballs.
Group 2: 1/6 of 36 pupils = 6 pupils. They took 6 * 2 = 12 meatballs.
Total meatballs taken so far: 90 + 12 = 102 meatballs.
Remaining meatballs: 150 - 102 = 48.
Remaining pupils: 36 - 18 - 6 = 12 pupils.
Meatballs per remaining pupil: 48 / 12 = 4.
Final Answers: (a) 48 meatballs, (b) 4 meatballs.

Answering after opening this box earns no Practice Points.