For what value of a does the linear equation (3a - 12)x + b + 7 = 0 have infinitely many solutions?

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A 3
B 4
C 0
D -4

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Answer: B. 4

Answer: B) 4
Explanation: An equation Ax + B = 0 has infinitely many solutions only if A = 0 and B = 0.
So 3a - 12 = 0, which gives a = 4 (and b + 7 = 0, so b = -7).

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For what value of a does the linear equation (3a - 12)x + b + 7 = 0 have infinitely many solutions?

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