Worksheet on Fractions for Class 7

Perfect fraction operations with our printable fractions worksheet pdf for Class 7. This advanced learning resource teaches students complex fraction calculations, mixed numbers and decimal conversions through challenging exercises and practical applications. Kids will master all fraction operations needed for higher mathematics confidently. Download free grade 7 fractions practice questions, and excel in numerical skills.

Solved Questions on Fractions

1. A rope of length 8 ⅗ metres is divided into five equal parts. What is the length of each part so obtained?

a) 1.12 metres
b) 1.32 metres
c) 1.52 metres
d) 1.72 metres

Answer: d) 1.72 metres

Explanation: Total length of rope =  8 ⅗ metres

A rope is divided into five equal parts.

Length of each part = 8 ⅗ metres ÷ 5
= 43/5 ÷ 5
= 43/5 × 1/5
= 43/25
= 1$\frac{\frac{\mathrm{18}}{}}{\frac{\mathrm{25}}{}}$ metres
= [1 + ($\frac{\frac{\mathrm{18}}{}}{\frac{\mathrm{25}}{}}$)] metres
= (1 + $\frac{\frac{\mathrm{18\; x\; 4}}{}}{\frac{\mathrm{25\; x\; 4}}{}}$) metres [Mutiplied by 4 to get denominator 100, to find decimals.]
= (1 + $\frac{\frac{\mathrm{72}}{}}{\frac{\mathrm{100}}{}}$) metres
= (1 + 0.72) metres
= 1.72 metres

2. A car runs 54 ¼ km consuming 2 litres of petrol. How much distance will it take to consume 1$\frac{\frac{2}{}}{\frac{7}{}}$ litre of petrol?

a) 34$\frac{\frac{1}{}}{\frac{8}{}}$ km
b) 34$\frac{\frac{3}{}}{\frac{8}{}}$ km
c) 34$\frac{\frac{5}{}}{\frac{8}{}}$ km
d) 34$\frac{\frac{7}{}}{\frac{8}{}}$ km

Answer: d) 34$\frac{\frac{7}{}}{\frac{8}{}}$ km

Explanation: Distance covered by consuming 2 litres of petrol = 54 ¼ km = 217/4 km

Distance covered by consuming 1 litre of petrol = 217/4 km ÷ 2
                                                                      = 217/8 km

Distance covered by consuming 1$\frac{\frac{2}{}}{\frac{7}{}}$ litre of petrol = 217/8 km × 1$\frac{\frac{2}{}}{\frac{7}{}}$ litre
                                                                         = 217/8 km × 9/7
                                                                          = 279/8 km
                                                                           = 34$\frac{\frac{7}{}}{\frac{8}{}}$ km

3. By how much does the sum of 37.786 and 29.576 exceed the sum of 38.789 and 23.548? 

a) 5.015
b) 5.025
c) 5.105
d) 5.125

Answer: b) 5.025

Explanation: Sum of 37.786 and 29.576 = 67.362

Sum of 38.789 and 23.548 = 62.337

Difference (Exceed by) =  67.362 −  62.337 = 5.025

4. What number should be added to 13$\frac{\frac{2}{}}{\frac{3}{}}$to get 12$\frac{\frac{5}{}}{\frac{7}{}}$?

a) $\frac{\frac{\mathrm{20}}{}}{\frac{\mathrm{21}}{}}$
b) $\frac{\frac{\mathrm{22}}{}}{\frac{\mathrm{21}}{}}$
c) − $\frac{\frac{\mathrm{20}}{}}{\frac{\mathrm{21}}{}}$
d) − $\frac{\frac{\mathrm{-22}}{}}{\frac{\mathrm{21}}{}}$

Answer: c) −$\frac{\frac{\mathrm{20}}{}}{\frac{\mathrm{21}}{}}$

Explanation: To find the number that should be added, subtract 13$\frac{\frac{2}{}}{\frac{3}{}}$ from 12$\frac{\frac{5}{}}{\frac{7}{}}$.

Required Number = 12$\frac{\frac{5}{}}{\frac{7}{}}$ − 13$\frac{\frac{2}{}}{\frac{3}{}}$

= $\frac{\frac{\mathrm{89}}{}}{\frac{7}{}}$ − $\frac{\frac{\mathrm{41}}{}}{\frac{3}{}}$
= $\frac{\frac{\mathrm{267\; -\; 287}}{}}{\frac{\mathrm{21}}{}}$  [LCM of 7 and 3 = 7 × 3 = 21]
= $\frac{\frac{\mathrm{-20}}{}}{\frac{\mathrm{21}}{}}$ or − $\frac{\frac{\mathrm{20}}{}}{\frac{\mathrm{21}}{}}$

5. When Katrina travelled 35 km by car, she found that (5/8)^th of her journey was still left. What was the total distance of the whole journey?

a) 93$\frac{\frac{1}{}}{\frac{3}{}}$ km
b) 93$\frac{\frac{2}{}}{\frac{3}{}}$ km
c) 93$\frac{\frac{1}{}}{\frac{8}{}}$ km
d) 93$\frac{\frac{3}{}}{\frac{8}{}}$ km

Answer: a) 93$\frac{\frac{1}{}}{\frac{3}{}}$ km

Explanation: Katrina travelled 35 km.

(5/8)^th of her journey was still left.

Fraction of her journey travelled = 1 − $\frac{\frac{5}{}}{\frac{8}{}}$

= $\frac{\frac{\mathrm{8\; -\; 5}}{}}{\frac{8}{}}$ [LCM of 1 and 8 is 8]
=  $\frac{\frac{3}{}}{\frac{8}{}}$

(3/8)^th of the total journey = Her journey travelled

⇒ (3/8)^th of the total journey = 35

⇒ Total journey = 35 × $\frac{\frac{8}{}}{\frac{3}{}}$
⇒ Total journey = $\frac{\frac{\mathrm{280}}{}}{\frac{3}{}}$
⇒ Total journey = 93$\frac{\frac{1}{}}{\frac{3}{}}$ km