**1. The freezing point of water is 32oF. Tim added potassium and found out that the freezing point went down by 8oF. What was the freezing point of the water with the added potassium?**

a) 23^{o}

b) 24^{o}

c) 25^{o}

d) 30^{o}

**Answer:** b) 24^{o}

**Explanation:** The freezing point of water = 32^{o}F

After adding potassium to it the freezing point goes down by 8^{o}F. (Since the freezing point goes down it is -8^{o}F)

The freezing point of the water with the added potassium is 32^{o}F - 8^{o}F = 24^{o}F.

**2. Solve the following:**

**i. 4 + (-4)** **ii.** **3 x 127 = ___ x 3**

a) i → 0, ii → 59

b) I → 1, ii → -127

c) i → 0, ii → 127

d) i → 1, ii → -59

**Answer:** c) i → 0, ii → 127

**Explanation: i.** 4 + (-4) = 4 - 4 = 0

**ii.** 3 x 127 = 127 x 3, Changing the position of numbers will not affect the result.

**3. Which of the following represents the additive inverse of -8?**

a) -8

b) 8

c) -1/8

d) 1/8

**Answer:** b) 8

**Explanation:** The additive inverse of a number is the number that when added to the original number, results in zero. The additive inverse of -8 is 8, since (-8) + 8 = 0.

**4. A man has $8,000 in his bank account. He withdrew $1,500 and then deposited $3,000. How much money does he have in his bank account now?**

a) $5800

b) $6230

c) $7869

d) $9500

**Answer:** d) $9500

**Explanation:** The man withdrew $1,500, so his bank account decreased by $1,500 and now has $8,000 - $1,500 = $6,500.

He then deposited $3,000, so his bank account increased by $3,000 and now has $6,500 + $3,000 = $9,500.

Therefore, the man now has $9,500 in his bank account.

**5. What is the result of (-4) - (-7)?**

a) -11

b) 3

c) -3

d) 11

**Answer:** b) 3

**Explanation:** When subtracting a negative number, it is the same as adding the positive value of that number. So, (-4) - (-7) becomes (-4) + 7, which equals 3.

**6. If a and b are integers, and a + b = 0, what is the value of a x b?**

a) - b

b) - b^{2}

c) - 2b

d) 2ab

**Answer:** b) -b^{2}

**Explanation:** If a + b = 0, then we know that a = -b. So, a x b = (-b) x b = -b^{2}, which is always negative.

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